Thursday, 11 July 2013
Saturday, 29 June 2013
Introduction to 8085 Architecture and Programming
Introduction to 8085 Architecture and Programming
Contents
1. Internal architecture of 8085 microprocessor
2. 8085 system bus
3. 8085 pin description.
4. 8085 functional description.
5. Programming model of 8085 microprocessor
6. Addressing modes.
7. Instruction set classification.
8. Instruction format.
9. Sample programs.
Control Unit
Generates signals within uP to carry out the instruction, which has been decoded. In
reality causes certain connections between blocks of the uP to be opened or closed, so
that data goes where it is required, and so that ALU operations occur.
Arithmetic Logic Unit
The ALU performs the actual numerical and logic operation such as ‘add’, ‘subtract’,
‘AND’, ‘OR’, etc. Uses data from memory and from Accumulator to perform
arithmetic. Always stores result of operation in Accumulator.
Registers
The 8085/8080A-programming model includes six registers, one accumulator, and
one flag register, as shown in Figure. In addition, it has two 16-bit registers: the stack
pointer and the program counter. They are described briefly as follows.
The 8085/8080A has six general-purpose registers to store 8-bit data; these are
identified as B,C,D,E,H, and L as shown in the figure. They can be combined as
register pairs - BC, DE, and HL - to perform some 16-bit operations. The
programmer can use these registers to store or copy data into the registers by using
data copy instructions.
Accumulator
The accumulator is an 8-bit register that is a part of arithmetic/logic unit (ALU). This
register is used to store 8-bit data and to perform arithmetic and logical operations.
The result of an operation is stored in the accumulator. The accumulator is also
identified as register A.
Flags
The ALU includes five flip-flops, which are set or reset after an operation according
to data conditions of the result in the accumulator and other registers. They are called
- Zero(Z)
- Carry (CY)
- Sign (S)
- Parity (P)
- Auxiliary Carry (AC) flags
they are listed in the Table and their bit positions in the flag register are shown in the Figure
below. The most commonly used flags are Zero, Carry, and Sign. The microprocessor
uses these flags to test data conditions.
For example, after an addition of two numbers, if the sum in the accumulator id larger
than eight bits, the flip-flop uses to indicate a carry -- called the Carry flag (CY) -- is
set to one. When an arithmetic operation results in zero, the flip-flop called the
Zero(Z) flag is set to one. The first Figure shows an 8-bit register, called the flag
register, adjacent to the accumulator. However, it is not used as a register; five bit
positions out of eight are used to store the outputs of the five flip-flops. The flags are
stored in the 8-bit register so that the programmer can examine these flags (data
conditions) by accessing the register through an instruction microprocessor.
The conditions (set or reset) of the flags are tested through the software
instructions. For example, the instruction JC (Jump on Carry) is implemented to
change the sequence of a program when CY flag is set. The thorough understanding
of flag is essential in writing assembly language programs.
Program Counter (PC)
This 16-bit register deals with sequencing the execution of instructions. This register
is a memory pointer. Memory locations have 16-bit addresses, and that is why this is a
16-bit register.
The microprocessor uses this register to sequence the execution of the instructions.
The function of the program counter is to point to the memory address from which the
next byte is to be fetched. When a byte (machine code) is being fetched, the program
counter is incremented by one to point to the next memory location
Stack Pointer (SP)
The stack pointer is also a 16-bit register used as a memory pointer. It points to a
memory location in R/W memory, called the stack. The beginning of the stack is
defined by loading 16-bit address in the stack pointer. The stack concept is explained
in the chapter "Stack and Subroutines."
Instruction Register/Decoder
Temporary store for the current instruction of a program. Latest instruction sent here
from memory prior to execution. Decoder then takes instruction and ‘decodes’ or
interprets the instruction. Decoded instruction then passed to next stage.
Memory Address Register
Holds address, received from PC, of next program instruction. Feeds the address bus
with addresses of location of the program under execution.
Control Generator
Generates signals within uP to carry out the instruction which has been decoded. In
reality causes certain connections between blocks of the uP to be opened or closed, so
that data goes where it is required, and so that ALU operations occur.
Register Selector
This block controls the use of the register stack in the example. Just a logic circuit
which switches between different registers in the set will receive instructions from
Control Unit.
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Complete Processor System Architecture
Complete Processor System Architecture
The
typical processor system consists of:
- CPU -central processing unit
- ALU -Arithmetic Logic unit
- Control Logic
- Registers,etc..
- Memory
- Input/Output interface
Interconnections between these units:
- Address Bus
- Data Bus
- Control Bus
§ Store 8-bit data (Registers,
Accumulator)
§
§ Perform arithmetic and logic
operations (ALU)
§
§ Test for conditions (IF / THEN)
§
§ Sequence the execution of
instructions
§
Store temporary data in RAM during execution
Download complete PPT Here
Introduction to Microprocessor Architecture
An Introduction to Microprocessor Architecture using intel 8085 as a classic processor
The typical processor system consists of:
- CPU (central processing unit)
- ALU (arithmetic-logic unit)
- Control Logic
- Registers, etc…
- Memory
- Input / Output interfaces
Interconnections between these units:
- Address Bus
- Data Bus
- Control Bus
**Read more: PPT HERE
SUBTRACTION OF TWO 8 BIT NUMBERS
SUBTRACTION OF TWO 8 BIT NUMBERS
AIM:
To perform the subtraction of two 8 bit numbers using 8085.
ALGORITHM:
1. Start the program by loading the first data into Accumulator.
Move the data to a register (B register).
2. Get the second data and load into Accumulator.
3. Subtract the two register contents.
4. Check for carry.
5. If carry is present take 2’s complement of Accumulator.
6. Store the value of borrow in memory location.
7. Store the difference value (present in Accumulator) to a memory
8. location and terminate the program.
PROGRAM:
MVI C, 00I Initialize C to 00
LDA 4150 Load the value to Acc.
MOV B, A Move the content of Acc to B register.
LDA 4151 Load the value to Acc.
SUB B
JNC LOOP Jump on no carry.
CMA Complement Accumulator contents.
INR A Increment value in Accumulator.
INR C Increment value in register C
LOOP: STA 4152 Store the value of A-reg to memory address.
MOV A, C Move contents of register C to Accumulator.
STA 4153 Store the value of Accumulator memory address.
HLT Terminate the program.
OBSERVATION:
Input: 06 (4150)
02 (4251)
Output: 04 (4152)
01 (4153)
RESULT:
Thus the program to subtract two 8-bit numbers was executed.
To perform the subtraction of two 8 bit numbers using 8085.
ALGORITHM:
1. Start the program by loading the first data into Accumulator.
Move the data to a register (B register).
2. Get the second data and load into Accumulator.
3. Subtract the two register contents.
4. Check for carry.
5. If carry is present take 2’s complement of Accumulator.
6. Store the value of borrow in memory location.
7. Store the difference value (present in Accumulator) to a memory
8. location and terminate the program.
PROGRAM:
MVI C, 00I Initialize C to 00
LDA 4150 Load the value to Acc.
MOV B, A Move the content of Acc to B register.
LDA 4151 Load the value to Acc.
SUB B
JNC LOOP Jump on no carry.
CMA Complement Accumulator contents.
INR A Increment value in Accumulator.
INR C Increment value in register C
LOOP: STA 4152 Store the value of A-reg to memory address.
MOV A, C Move contents of register C to Accumulator.
STA 4153 Store the value of Accumulator memory address.
HLT Terminate the program.
OBSERVATION:
Input: 06 (4150)
02 (4251)
Output: 04 (4152)
01 (4153)
RESULT:
Thus the program to subtract two 8-bit numbers was executed.
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